Find the compound interest on Rs 12000 for one and half years at 8% per annum compounded half yearly

Knockout CUET (Physics, Chemistry and Mathematics)

Complete Study Material based on Class 12th Syllabus, 10000+ Question Bank, Unlimited Chapter-Wise and Subject-Wise Mock Tests, Study Improvement Plan.

₹ 7999/- ₹ 4999/-

Buy Now
Knockout CUET (Physics, Chemistry and Biology)

Complete Study Material based on Class 12th Syllabus, 10000+ Question Bank, Unlimited Chapter-Wise and Subject-Wise Mock Tests, Study Improvement Plan.

₹ 7999/- ₹ 4999/-

Buy Now
Knockout JEE Main (Six Month Subscription)

- AI Coach Study Modules, - Unlimited Mock Tests, - Study Improvement Plan.

₹ 9999/- ₹ 8499/-

Buy Now
Knockout JEE Main (Nine Month Subscription)

- AI Coach Study Modules, - Unlimited Mock Tests, - Study Improvement Plan.

₹ 13999/- ₹ 12499/-

Buy Now
Knockout NEET (Six Month Subscription)

- AI Coach Study Modules, - Unlimited Mock Tests, - Study Improvement Plan.

₹ 9999/- ₹ 8499/-

Buy Now

What will be the compound interest on Rs. 5000 if it is compounded half-yearly for 1 year 6 months at 8 % per annum.

Answer

Verified

Hint: The amount can be calculated using the given data and the formula:
$A = P{\left( {1 + \dfrac{R}{{100}}} \right)^t}$ where,
A = Amount
P = Principal
R = Rate
T = Time
Remember to half the rate and double the time as the principal is compounded half-yearly.
Then, the compound interest can be calculated using the relationship:
Amount = Principal + Compound Interest

Complete step-by-step answer:
Given:
Principal (P) = Rs. 5000
Rate (R) = 8 %
As it is compounded half yearly, the rate will reduce to half
$R = \dfrac{8}{2}\% $
R = 4 %
Time (t) = 1 year 6 months
= $\left( {1 + \dfrac{1}{2}} \right)yrs$
 $\left(
 \because 12m = 1yr \\
 6m = \dfrac{1}{{12}} \times 6 \\
 6m = \dfrac{1}{2}yrs \\
 \right)$
= $\dfrac{3}{2}yrs$
As it is compounded half yearly, the time will be doubled:
$t = 2 \times \dfrac{3}{2}yrs$
T = 3 yrs.
Substituting these values in the formula of Amount, we get:
$A = P{\left( {1 + \dfrac{R}{{100}}} \right)^t}$
$A = 5000{\left( {1 + \dfrac{4}{{100}}} \right)^3}$
$A = 5000{\left( {\dfrac{{104}}{{100}}} \right)^3}$
$A = 5000 \times \dfrac{{104}}{{100}} \times \dfrac{{104}}{{100}} \times \dfrac{{104}}{{100}}$
A = 5624.32
The amount is equal to Rs. 5624.32
Now,
Amount = Principal + Compound Interest
Compound Interest = Amount – Principal
Substituting the values, we get:
Compound Interest = 5624.32 – 5000
Compound Interest = 624.32
Therefore, the compound interest is Rs. 624.32 on Rs. 5000 if it is compounded half yearly for 1 year 6 months at 8 % per annum.

Note: We make the respective changes when compounded half-yearly because:
Rate is halved. The rate is generally given for a year (per annum) but when we require for half-yearly, the per annum rate is also reduced to half.
Time is doubled.When we talk about half a year (6 months), it occurs twice every year (6 + 6 = 12) and hence the time is doubled.

Solution : Principle`=` Rs .`12000`<br>Time`(n) = 2`year<br>Rate`= 20%`<br>Now , `A= P(1+R/100)^n`<br>`A= 12000 ( 1+20/100)^2`<br>`A= 12000 (1+1/5)^2`<br>`A= 12000 (6/5)^2`<br>`A= 12000xx 36/25`<br>`A=17280`

The compound interest (in Rs.) on a sum of Rs. 12,000 at 10% per annum for 1.5 years, interest compounded half-yearly, is:

  1. Rs. 1,750
  2. Rs. 1,900
  3. Rs. 1,821.50
  4. Rs. 1,891.50

Answer (Detailed Solution Below)

Option 4 : Rs. 1,891.50

Free

10 Questions 10 Marks 7 Mins

Given:

A sum = Rs. 12,000

Rate = 10% per annum

And time = 1.5 years.

Formula used:

Amount = Principal{1 + (R/100)}n

Where n = time in years and R = rate percentage/annum

Compund interest = Amount - Principal

If time = n years, rate = R% and interest compounded half-yearly

Then time = 2n  and rate = (R/2)%

Calculation:

Interest compounded half-yearly:

Then time = 2 × 1.5

⇒ 3 years

And the rate = 10/2

⇒ 5% 

Amount = 12000 × {1 + (5/100)}3

⇒ 12000 × {1 + (1/20)}3

⇒ 12000 × {(20 + 1)/20}3

⇒ 12000 × (21/20)3

⇒ 12000 × (9261/8000)

⇒ 12 × 9261/8

⇒ 1,11,132/8

⇒ Rs. 13891.5

Compound interest = amount - principal

⇒ 13891.5 - 12000

⇒ Rs. 1891.5

∴ The compound interest is Rs. 1891.5

Last updated on Sep 21, 2022

The RRB (Railway Recruitment Board) has released the Result, and Cut Off marks for the CBAT (Computer Based Aptitude Test) stage for Pay Level 6. The result and cut-off marks are announced for the RRB Chandigarh, Bhopal & Chennai regions for the recruitment cycle 2021. The exam is conducted to fill up a total number of 35281 vacant posts. Candidates who are qualified for the Computer Based Aptitude Test will be eligible for the next round, which will be Document Verification & Medical Exam. The candidates with successful selection under RRB NTPC will get a salary range between Rs. 19,900 to Rs. 35,400. Know the RRB NTPC Result here.

Let's discuss the concepts related to Interest and Compound Interest. Explore more from Quantitative Aptitude here. Learn now!

What is the compound interest on a sum of Rs 12000 for 2 years at 8% pa when the interest is compounded annually nearest to a rupee )?

Hence, the compound interest is Rs. 2,520.

What is the compound interest of 12000?

[or directly=Rs. 14520 - Rs. 12000 = Rs. 2520]

What is the compound interest in RS on a sum of Rs 12600 for 1 ½ years at 20% per annum if the interest is compounded half yearly nearest to a rupee?

∴ The compound interest incurred is Rs. 4171.

How do you calculate compound interest in one and a half years?

The formula for calculation of compound interest for half year is CI = p(1 + {r/2}/100)2t. - p. Here in this formula 'A' is the final amount, 'p' is the principal, and 't' is the time in years.