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Given, a fair coin is flipped 10 times. We have to find the probability of getting at least one tail. Probability of getting at least one coin is the complement of 1 minus the probability Probability that tail will occur when a coin is flipped is given by p = 1 / 2 The probability of getting at least one tail is equal to one minus the probability of all heads. P = 1 - (1 / p)10 The probability of head all 10 times is (1 / 2)10 (1 / 2)10 = 1 / 1024 Now, P = 1 - (1 / p)10 = 1 - (1 / 1024) = (1024 - 1) / 1024 P = 1023 / 1024 Therefore, the probability of getting at least one tail is 1023 / 1024. If you flip a fair coin 10 times. What is the probability of getting at least one tail?Summary: If you flip a fair coin 10 times. The probability of getting at least one tail is 1023 / 1024. Want to join the conversation?
What is the probability of flipping 10 tails with 10 coins?To extend this out to ten tails in a row - the probability that you already got that is 1/1024.
How many possibilities are there if you flip a coin 10 times?How many different sequences of heads and tails are possible if you flip a coin 10 times? Answer Since each coin flip can have 2 outcomes (heads or tails), there are 2·2·... 2 = 210 = 1024 ≈ 1000 possibile outcomes of 10 coin flips.
What is the probability of flipping a coin 10 times and not getting a heads for any flip?I expect it to be much higher than tails. There is a 0.5 probability of getting a tail on a single coin, so the probability of getting 10 tails is (0.5)^10 = 9.766 * 10 ^ -4 or 0.0009766. Is it possible to flip a coin 100 times and get the same result?
What is the probability if I flip a fair coin with heads and tails ten times in a row that I get at least 88 heads?The answer is the probability, that out of ten tosses of the coin, at least 8 show heads, is 0.0547 .
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