Post your comments here:Name *: Email : (optional) » Your comments will be displayed only after manual approval. What is the probability of getting 3 heads while tossing 3 coins?(i) Let E1 denotes the event of getting three heads. Hence the required probability is 0.28.
When 3 unbiased coins are tossed once what is the probability of getting all heads?` <br> `therefore` P (getting all heads) `= P(E_(1)) = (n(E_(1)))/(n(S)) = 1/8.
What is the probability of getting exactly two heads in three throws of an unbiased coin?Hence the probability of getting exactly two heads is 83.
What is the probability of getting at most 3 heads when four unbiased coins are tossed simultaneously?P(at most 3-H) = P(0)+P(1) + P(2) + P(3) = (1 + 4 + 6 + 4)/16 = 15/16.
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