Which of the following specifies that an entity instance of the supertype does not have to belong to any subtype?

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Which of the following specifies that an entity instance of the supertype is allowed not to belong to any subtype?

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Which of the following rules specifies that each entity instance of the supertype Cannot be a member of more than one the subtypes simultaneously in the relationship?

The disjoint rule specifies that if an entity instance of the supertype is a member of one subtype, it MUST simultaneously be a member of another subtype. Generalization is a top-down process.

Is the rule that specifies that an entity instance of a supertype may not simultaneously be a member of two or more subtypes?

Disjoint rule. Specifies that if an entity instance (of the supertype) is a member of one subtype, it cannot simultaneously be a member of two (or more) subtypes. Overlap rule. Specifies that an entity instance can simultaneously be a member of two (or more) subtypes.

What type of constraints in Supertype that an instance of a supertype must also be a member of at least one subtype?

Completeness Constraints: Whether an instance of a supertype must also be a p yp member of at least one subtype. b) Partial Specialization rule Figure 3-6 Examples of completeness constraints (cont.)