Correct Answer: Description for Correct answer: \( \Large 3X+2Y=10\qquad ...(2)\) \( \Large (1)\) as the regression of \( \Large Y\) on \( \Large X\) \( \Large 6Y=6-X\) \( \Large Y=1-\frac{X}{6}\text{ or }b_{yx}=-\frac{1}{6}\) from \( \Large (2),\ 3X=10-2Y\Rightarrow X=\frac{10}{3}-\frac{2Y}{3}\) or \( \Large b_{xy}=-\frac{2}{3},\ r=-\sqrt{\frac{1}{6} \times \frac{2}{3}}=-0.333\) Part of solved Aptitude questions and answers : >> Aptitude How do you find the regression of two lines?A regression coefficient is the same thing as the slope of the line of the regression equation. The equation for the regression coefficient that you'll find on the AP Statistics test is: B1 = b1 = Σ [ (xi – x)(yi – y) ] / Σ [ (xi – x)2]. “y” in this equation is the mean of y and “x” is the mean of x.
How do you find the regression line X on Y and Y on X?If Y depends on X then the regression line is Y on X. Y is dependent variable and X is independent variable. If X depends on Y, then regression line is X on Y and X is dependent variable and Y is independent variable. The regression equation Y on X is Y = a + bx, is used to estimate value of Y when X is known.
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The two regression lines of a sample are x + 6y=6 and 3x+2y 0 find the correlation coefficient
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